Recognize a quadratic
The highest power of the variable is 2. In standard form, the leading coefficient cannot be zero.
Amit ShrivastavaMentor · Digital SAT
Recognize the form, choose the shortest path, and connect every solution to its graph and context.
Don’t memorize these as isolated formulas. Each representation reveals different information.
The highest power of the variable is 2. In standard form, the leading coefficient cannot be zero.
Standardax² + bx + c
Vertexa(x − h)² + k
Factoreda(x − r₁)(x − r₂)
If a product equals zero, at least one factor must be zero.
Identify a, b, and c—including their signs—before substituting.
The axis of symmetry passes through the vertex.
Roots show where the output is zero. The vertex represents a maximum or minimum. The sign of a tells the opening direction.
A quadratic model may produce two algebraic solutions, but a length, time, or population problem can make one solution invalid.
The best method depends on what the question gives and what it asks.
Set each factor equal to zero. Avoid expanding unless the question requires coefficients.
Read (h, k) directly from a(x − h)² + k and interpret the maximum or minimum.
Find two numbers with the required product and sum, then apply the zero-product property.
Use a graph or the quadratic formula, then verify the requested value and context.
Follow a complete reasoning chain instead of stopping after finding two numbers.
A projectile’s height is modeled by h(t) = −5t² + 20t + 25, where t is time in seconds. At what positive time does the projectile reach the ground?
Ground means height is zero.
−5t² + 20t + 25 = 0
Simplify by dividing by −5.
t² − 4t − 5 = 0
Factor.
(t − 5)(t + 1) = 0
Interpret both solutions.
t = 5 or t = −1
Negative time is outside the model’s meaningful domain.
01Losing the sign of bWrite coefficients with signs before substitution.
02Forgetting ±A square-root step often produces two candidates.
03Confusing vertex and rootThe vertex is a turning point; roots are x-intercepts.
04Keeping an impossible valueCheck units, restrictions, and the original context.
Choose an answer, check it, then read the reasoning—not just the letter.
Vertex form a(x − h)² + k displays the vertex (h, k), so the answer is B.
D = 4² − 4(1)(8) = −16. A negative discriminant means no real solutions.
Factor as (x − 4)(x − 5) = 0. The roots are 4 and 5, so the smaller solution is 4.
x = −b/(2a) = −(−6)/(2·1) = 3.
Quadratic questions become easier when you identify what each form reveals and verify the final value against the question’s context.